PaddleOCR-EAST
目录
写在前面:基于PaddleOCR代码库对其中所涉及到的算法进行代码简读,如果有必要可能会先研读一下原论文。
Abstract
- 论文链接:arxiv
- 应用场景:文本检测
- 代码配置文件:configs/det/det_r50_vd_east.yml
Train
PreProcess
class EASTProcessTrain(object):
def __init__(self,
image_shape=[512, 512],
background_ratio=0.125,
min_crop_side_ratio=0.1,
min_text_size=10,
**kwargs):
self.input_size = image_shape[1]
self.random_scale = np.array([0.5, 1, 2.0, 3.0])
self.background_ratio = background_ratio
self.min_crop_side_ratio = min_crop_side_ratio
self.min_text_size = min_text_size
...
def __call__(self, data):
im = data['image']
text_polys = data['polys']
text_tags = data['ignore_tags']
if im is None:
return None
if text_polys.shape[0] == 0:
return None
#add rotate cases
if np.random.rand()
Architecture
Backbone
采用resnet50_vd,得到1/4、1/8、1/16以及1/32倍共计4张降采样特征图。
Neck
基于Unect decoder架构,完成自底向上的特征融合过程,从1/32特征图逐步融合到1/4的特征图,最终得到一张带有多尺度信息的1/4特征图。
def forward(self, x):
# x是存储4张从backbone获取的特征图
f = x[::-1] # 此时特征图从小到大排列
h = f[0] # [b,512,h/32,w/32]
g = self.g0_deconv(h) # [b,128,h/16,w/16]
h = paddle.concat([g, f[1]], axis=1) # [b,128+256,h/16,w/16]
h = self.h1_conv(h) # [b,128,h/16,w/16]
g = self.g1_deconv(h) # [b,128,h/8,w/8]
h = paddle.concat([g, f[2]], axis=1) # [b,128+128,h/8,w/8]
h = self.h2_conv(h) # [b,128,h/8,w/8]
g = self.g2_deconv(h) # [b,128,h/4,w/4]
h = paddle.concat([g, f[3]], axis=1) # [b,128+64,h/4,w/4]
h = self.h3_conv(h) # [b,128,h/4,w/4]
g = self.g3_conv(h) # [b,128,h/4,w/4]
return g
Head
输出分类头和回归头(quad),部分参数共享。
def forward(self, x, targets=None):
# x是融合后的1/4特征图,det_conv1和det_conv2用于进一步加强特征抽取
f_det = self.det_conv1(x) # [b,128,h/4,w/4]
f_det = self.det_conv2(f_det) # [b,64,h/4,w/4]
# # [b,1,h/4,w/4] 用于前、背景分类,注意kernel_size=1
f_score = self.score_conv(f_det)
f_score = F.sigmoid(f_score) # 获取相应得分
# # [b,8,h/4,w/4],8的意义:dx1,dy1,dx2,dy2,dx3,dy3,dx4,dy4
f_geo = self.geo_conv(f_det)
# 回归的range变为:[-800,800],那么最终获取的文本框的最大边长不会超过1600
f_geo = (F.sigmoid(f_geo) - 0.5) * 2 * 800
pred = {'f_score': f_score, 'f_geo': f_geo}
return pred
Loss
分类采用dice_loss,回归采用smooth_l1_loss。
class EASTLoss(nn.Layer):
def __init__(self,
eps=1e-6,
**kwargs):
super(EASTLoss, self).__init__()
self.dice_loss = DiceLoss(eps=eps)
def forward(self, predicts, labels):
"""
Params:
predicts: {'f_score': 前景得分图,'f_geo': 回归图}
labels: [imgs, l_score, l_geo, l_mask]
"""
l_score, l_geo, l_mask = labels[1:]
f_score = predicts['f_score']
f_geo = predicts['f_geo']
# 分类loss
dice_loss = self.dice_loss(f_score, l_score, l_mask)
channels = 8
# channels+1的原因是最后一个图对应了短边的归一化系数(后面会讲),前8个代表相对偏移的label
# [[b,1,h/4,w/4], ...]共9个
l_geo_split = paddle.split(
l_geo, num_or_sections=channels + 1, axis=1)
# [[b,1,h/4,w/4], ...]共8个
f_geo_split = paddle.split(f_geo, num_or_sections=channels, axis=1)
smooth_l1 = 0
for i in range(0, channels):
geo_diff = l_geo_split[i] - f_geo_split[i] # diff=label-pred
abs_geo_diff = paddle.abs(geo_diff) # abs_diff
# 计算abs_diff中小于1的且有文本的部分
smooth_l1_sign = paddle.less_than(abs_geo_diff, l_score)
smooth_l1_sign = paddle.cast(smooth_l1_sign, dtype='float32')
# smoothl1 loss,大于1和小于1的两个部分对应loss相加,只不过这里
Dice Loss
公式:
代码:
class DiceLoss(nn.Layer):
def __init__(self, eps=1e-6):
super(DiceLoss, self).__init__()
self.eps = eps
def forward(self, pred, gt, mask, weights=None):
# mask代表了有效文本的mask,有文本的地方是1,否则为0
assert pred.shape == gt.shape
assert pred.shape == mask.shape
if weights is not None:
assert weights.shape == mask.shape
mask = weights * mask
intersection = paddle.sum(pred * gt * mask) # 交集
union = paddle.sum(pred * mask) + paddle.sum(gt * mask) + self.eps # 并集
loss = 1 - 2.0 * intersection / union
assert loss
SmoothL1 Loss
公式:
Infer
PostProcess
class EASTPostProcess(object):
def __init__(self,
score_thresh=0.8,
cover_thresh=0.1,
nms_thresh=0.2,
**kwargs):
self.score_thresh = score_thresh
self.cover_thresh = cover_thresh
self.nms_thresh = nms_thresh
...
def __call__(self, outs_dict, shape_list):
score_list = outs_dict['f_score'] # shape=[b,1,h//4,w//4]
geo_list = outs_dict['f_geo'] # shape=[b,8,h//4,w//4]
if isinstance(score_list, paddle.Tensor):
score_list = score_list.numpy()
geo_list = geo_list.numpy()
img_num = len(shape_list)
dt_boxes_list = []
for ino in range(img_num):
score = score_list[ino]
geo = geo_list[ino]
# 根据score、geo以及一些预设阈值和locality_nms操作拿到检测框
boxes = self.detect(
score_map=score,
geo_map=geo,
score_thresh=self.score_thresh,
cover_thresh=self.cover_thresh,
nms_thresh=self.nms_thresh)
boxes_norm = []
if len(boxes) > 0:
h, w = score.shape[1:]
src_h, src_w, ratio_h, ratio_w = shape_list[ino]
boxes = boxes[:, :8].reshape((-1, 4, 2))
# 文本框坐标根于缩放系数映射回输入图像上
boxes[:, :, 0] /= ratio_w
boxes[:, :, 1] /= ratio_h
for i_box, box in enumerate(boxes):
# 根据宽度比高度大这一先验,将坐标调整为以“左上角”点为起始点的顺时针4点框
box = self.sort_poly(box.astype(np.int32))
# 边长小于5的再进行一次过滤,拿到最终的检测结果
if np.linalg.norm(box[0] - box[1]) score_thresh)
if len(xy_text) == 0:
return []
# 按y轴从小到大的顺序对这些点进行排序
xy_text = xy_text[np.argsort(xy_text[:, 0])]
# 恢复成基于原图的文本框坐标
text_box_restored = self.restore_rectangle_quad(
xy_text[:, ::-1] * 4, geo_map[xy_text[:, 0], xy_text[:, 1], :])
# shape=[n,9] 前8个通道代表x1,y1,x2,y2的坐标,最后一个通道代表每个框的得分
boxes = np.zeros((text_box_restored.shape[0], 9), dtype=np.float32)
boxes[:, :8] = text_box_restored.reshape((-1, 8))
boxes[:, 8] = score_map[xy_text[:, 0], xy_text[:, 1]]
try:
import lanms
boxes = lanms.merge_quadrangle_n9(boxes, nms_thresh)
except:
print(
'you should install lanms by pip3 install lanms-nova to speed up nms_locality'
)
# locality nms,比传统nms要快,因为进入nms中的文本框的数量要比之前少很多。前面按y轴排序其实是在为该步骤做铺垫
boxes = nms_locality(boxes.astype(np.float64), nms_thresh)
if boxes.shape[0] == 0:
return []
# 最终还会根据框预测出的文本框内的像素在score_map上的得分再做一次过滤,感觉有一些不合理,因为score_map
# 上预测的是shrink_mask,会导致框内有很多背景像素,拉低平均得分,可能会让一些原本有效的文本框变得无效
# 当然这里的cover_thresh取的比较低,可能影响就比较小
for i, box in enumerate(boxes):
mask = np.zeros_like(score_map, dtype=np.uint8)
cv2.fillPoly(mask, box[:8].reshape(
(-1, 4, 2)).astype(np.int32) // 4, 1)
boxes[i, 8] = cv2.mean(score_map, mask)[0]
boxes = boxes[boxes[:, 8] > cover_thresh]
return boxes
def nms_locality(polys, thres=0.3):
def weighted_merge(g, p):
"""
框间merge的逻辑:坐标变为coor1*score1+coor2*score2,得分变为score1+score2
"""
g[:8] = (g[8] * g[:8] + p[8] * p[:8]) / (g[8] + p[8])
g[8] = (g[8] + p[8])
return g
S = []
p = None
for g in polys:
# 由于是按y轴排了序,所以循环遍历就可以了
if p is not None and intersection(g, p) > thres:
# 交集大于阈值那么就merge
p = weighted_merge(g, p)
else:
# 不能再merge的时候该框临近区域已无其他框,那么其加入进S
if p is not None:
S.append(p)
p = g
if p is not None:
S.append(p)
if len(S) == 0:
return np.array([])
# 将S保留下的文本框进行标准nms,略
return standard_nms(np.array(S), thres)
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